Find the perimeter of a regular heptagon with consecutive vertices at a(? 1,? 2) and b(4, 10)

The perimeter is ≈ 59.808 units

Explanation:

A regular heptagon is a polygon that has 7 equal sides.

To get its perimeter, we need to get the length of only one side and multiply it by 7

1- getting side length:

We are given that there are two consecutive vertices at (1,2) and (4,10)

The length of the side can be calculated using the distance formula as follows:

Length = units

2- getting the perimeter:

Perimeter = 7 * side length

Perimeter = ≈ 59.808 units

Hope this helps :)

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

step-by-step explanation: