Maria is ten years older than josé, and next year she will be twice as old as josé. how old are they now?

Maria's age now is 19 years old

Jose's age now is 9 years old

Explanation:

Assume that Maria's current age is x and that Jose's current age is y

We are given that:

1- Maria is 10 years older than Jose.

This means that:

x = y + 10 > equation I\

2- Next year, Maria will be twice as old as Jose.

This means that:

Maria's age next year = 2 * Jose's age next year

x + 1 = 2(y+1)

x + 1 = 2y + 2 > equation II

Substitute with equation I in equation II and solve for y as follows:

x + 1 = 2y + 2

y + 10 + 1 = 2y + 2

y + 11 = 2y + 2

2y - y = 11 - 2

y = 9

Substitute with y in equation I to get x as follows:

x = y + 10

x = 9 + 10

x = 19

Based on the above calculations:

Maria's current age = x = 19 years old

Jose's current age = y = 9 years old

Hope this helps :)

n

step-by-step explanation:

no this is a nonlinear negative