Determine which postulate or theorem can be used to prove that abc=dcb

Answer with explanation:

In Δ ABC and ΔD BC

∠A=∠DGiven

∠ABC=∠DCBEach being 90° given in the Diagram.

Side, BC is Common.

⇒⇒Δ ABC ≅ ΔD BC[AAS]

When two triangles are congruent , their areas are equal.

So, Area(ABC)=Area (DCB)

Option B :⇒ A AS

AAS is the correct answer ( apex)

Step-by-step explanation:

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