Easy brainliest

reasoning write an inequality that describes the region of the coordinate plane not included in the graph of y < 5x +1.

(-1, 1)

Step-by-step explanation:

Anything that is greater than -1/2 on the x-axis is included.

i got u

The slope is  

− 2 5 .

The y-intercept is  

1 .

The point is  

( 0 , 1 ) .

The x-intercept is  

2 5 .

The point is  

( 2 5 , 0 ) .

Explanation:

y < − 2 5 x + 1

is in the slope-intercept form of a linear equation,  

y = m x + b , where  m

is the slope and  b

is the y-intercept. The y-intercept is the value of  y

when  x  is  0 .

Find the  

x  and  y

intercepts.

The y-intercept is  + 1 .

The point for the y-intercept is  

( 0 , 1 ) .

Find the  x

intercept by substituting  

0  for  y

and solving for  

x .  0 = − 2 5 x + 1  

Subtract  1

from both sides.

− 1 = − 2 5 x

Multiply both sides by  

5 5 × − 1 = − 2x − 5 = − 2 x

Divide both sides by  − 2 .  − 5 − 2 = x5 2 = x  

Switch sides.

x = 5 2

The x-intercept is  

5 2 .

The point for the x-intercept is  

( 5 2 , 0 ) .

Plot the two points on a graph. Draw a straight dashed line through the points to indicate that the line is not part of the inequality. Then shade the area below the line.

graph{y<-2/5x+1 [-10, 10, -5, 5]}

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.