Match the function with the graph.

d. y = 1/(x + 2) + 3

Step-by-step explanation:

From the given graph, the vertical asymptote at x = -2, so the denominator expression is (x + 2).

The horizontal asymptote at y = 3.

Therefore, the function y = 1/(x+2)   + 3

d = 1/ (x + 2)  + 3

Hope you will understand the concept.

Thank you.

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option