What are the solutions of the equation x^4-5x^2-36=0? use factoring to solve.

+3 and -3, and + 2i or - 2i, which is the second answer.

Step-by-step explanation:

(x^2 -9)(x^2 + 4) is the factorization. Now set each side equal to zero:

(x^2-9) = 0; so x^2= 9, and x = square root of 9 which is +3 or -3.

(x^2) + 4 = 0; so x^2 = -4, and x will equal the square root of NEGATIVE 4, which is plus or minus 2i

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