The sum of 2 consecutive #s is 1893. find the numbers

n=946 and n=947

Step-by-step explanation:

n + (n+1) = 1893.

2n + 1 = 1893.

2n + 1 - 1 = 1893 - 1.

2n = 1892

2n/2= 1892/2

n=946

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18