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the kilopascal is a unit of measure for atmospheric pressure. suppose the atmospheric air pressure at sea level is about 96 kilopascals. for every 1000-m increase in altitude, the pressure decreases about 11.4%. what is the approximate pressure at an altitude of 4000 m? the pressure at an altitude of 4000 m is about kilopascals.

The pressure at 4000 m is about 59 kilopascals

Step-by-step explanation:

The equation is of the form

y= a b^x

where a is the initial value, b is 1 - percent decrease, and x is the number of 1000 m increases

a = 96 kilopascals

b = 1- 11.4%

   =1-.114

   = .886

y = 96 (.886)^x

We go up 4000 m  so x = 4000/1000 = 4

y = 96(.886) ^4

y = 59.156997121536

The pressure at 4000 m is about 59 kilopascals

Step-by-step explanation:

Suppose the atmospheric air pressure at sea level is about 96 kilopascals.

For every 1000-m increase in altitude, the pressure decreases about 11.4%.

The approximate pressure at an altitude of 1000 m = 96*(1-11.4%) = 96*0.886

The pressure at an altitude of 2000 m is = 96*0.886*0.886

The pressure at an altitude of 4000 m is = 96*0.886*0.886*0.886*0.886

= 59.157 kilopascal

(3x-8) or (3x+8)

step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)