Ahouse and lot together cost more than $89,000. the house costs $1000 more than seven times the cost of the lot. how much does the lot cost?

$11,000

Step-by-step explanation:

Using one variable and an expression, you can set up an equation to solve for the cost of both the lot and the house.  

x = the cost of the lot

7x + 1000 = the cost of the house since the houses costs ($1000 more than seven times the cost of the lot)

Since the cost of the house and lot together is more than $89,000:

x + 7x + 1000 > 89,000

Combine like terms:  8x + 1000 > 89,000

Subtract 1000 from both sides:  8x + 1000 - 1000 > 89,000 - 1000 or 8x > 88000

Divide by 8 on both sides: 8x/8 > 88,000/8

x > $11,000

the one that has a slope of 1/2 and is positive.

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