Mathematics, 04.02.2020 19:57, awesomegrill

Factor completely:
12x^5 + 6x^3 + 8x^2

a- prime
b- 2(6x^5+3x^3+4x^2)
c- 2x(6x^4+6x^2+4x)
d- 2x^2(6x^3+3x+4)

Answers: 1

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Factor completely:
12x^5 + 6x^3 + 8x^2

a- prime
b- 2(6x^5+3x^3+4x^2)
...

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Factor completely: 12x^5 + 6x^3 + 8x^2 a- prime b- 2(6x^5+3x^3+4x^2) c- 2x(6x^4+6x^2+4x) d- 2x^2(6x^3+3x+4)

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Factor completely:
12x^5 + 6x^3 + 8x^2

a- prime
b- 2(6x^5+3x^3+4x^2)
c- 2x(6x^4+6x^2+4x)
d- 2x^2(6x^3+3x+4)