Arectangular garden is 6 feet long and 4 feet wide. a second rectangular garden has dimensions that are double the dimensions of the first garden. what is the percent of change in perimeter from the first garden to the second garden?

100 percent increase

Step-by-step explanation:

1st garden

Length = 6 ft

Width = 4 ft

Perimeter = 2 (l+w)

                 = 2 (6+4) = 2(10) = 20

2nd garden

The length and width are 2 times the 1st garden

Length = 2 *6 = 12

Width = 2 *4 = 8

Perimeter = 2 (l+w)

                 = 2 (12+8) = 2(20) = 40

Percent change = (new - old )/old * 100 percent

The 1st garden is the old garden = 20  and the 2nd garden is the new garden = 40

Substituting in

Percent change = (40-20)/20 = 20/20 =100 *100 percent

                            = 100 percent increase

it’s supposed to be -4+45=41

step-by-step explanation: