The measure of ? b is (3x – 4 )° and the measure of ? d is (2x – 6)°. what are the measures of angles b and d? m? b = ° m? d = °

B(3x-4) and D(2x-6)

first find the value of x.

3x-4 + 2x-6=90

3x+2x-4-6=90

5x-10=90

5x=90+10

5x=100 divid 5 both sides with.

u will get

x=20

then now find the angles of B and D.

B (3x-4) +D (2x-6)=90

so for angle of B° is.

3x-4=90.

B°+3(20)-4=90

B°+60-4=90

B°+56=90

B°=90-56

B=34° ANs.

for angle D°

D°2x-6=90

D°+2(20)-6=90

D°+40-6=90

D°+36=90

D°=90-36

D=56° ANs.

B = 110

and

D = 70

the correct answer to your question is a. 4^4

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option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.