Ashoe box measures 15 in by 7 in by 4 1/2 in. what is the surface area of the box

408

Step-by-step explanation:

The method that we are going to use in this problem is using nets to find the surface area. In this method we picture the box being cut in different areas to make one large piece of the box (Refer to Image 1).

After we open up the box we can then solve for the surface area of the larger area. (Refer to Image 2)

Since we have the measurements of each area, we solve it like so.

First we add the total length of the cut up box.

4 1/2 + 15 + 4 1/2 + 15 = 39 inches

Now we also know that the width of the box is 7 inches. We just simply multiple both the length of the width together.

7 x 39 = 273

Now that we have the value of the larger area of the box, we can then proceed to find the value of one of the extra flaps.

15 x 4 1/2 = 67.5

Now that we solved for one side, we can assume that the other side will have the same surface area as they have the same values.

67.5 x 2 = 135

Now we simply add up the larger area to the value of the two smaller areas and we end up with our answer.

273 + 135 = 408

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.