What is the equation of a circle with center (2 -3) and radius 3

Choice A

x^2+y^2=r^2 is the mother function of a circle centered at the origin with radius r.

then x^2+y^2=9 is the equation of a circle with radius 3 centered at the origin

to translate the graph 2 unites to the right, add the opposite of 2 which is -2 to the x value inside the function, and to translate the graph 3 units down, then add the opposite which is 3 to the y value inside the function.

which makes the equation became (x-2)^2+(y+3)^2=9 and that is choice A  

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

the answer is 24

step-by-step explanation: