Let f(x) =x+7 and g(x)= x-4. find f(x) times g(x)

x² + 3x - 28

Step-by-step explanation:

We need f(x)*g(x), or

(x + 7)(x - 4)

Use FOIL to multiply, Foil is Firsts, Outsides, Insides, Lasts.  It tells you the terms to multiply together...

Firsts:         x(x) = x²

Outsides:    x(-4) = -4x

Insides:      7(x) = 7x

Lasts:        (7)(-4) = -28

So we have

x² - 4x + 7x - 28

simplify to

x² + 3x - 28

2 and 1.

step-by-step explanation:

plug in each answer. 0 doesn't work, 1 does. so does 2. 4 doesn't:

0 = 1 is not true.

2 = 2 is true.

4 = 4 is true.

8 = 16 is not true.

hope this !

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq