Write the equation of the line parallel to 3x-y=7 that passes through point (-5, -3)

The equation of the line is y =3x+12

Step-by-step explanation:

The first step is to rewrite the equation of the line in the slope-intercept form in order to identify the slope of the line. The re-written equation is; y = 3x-7. This implies that the slope of the line is 3. Since the two lines will be parallel they will be having equal slopes of 3. The slope-intercept form of the equation of this line will be; y =3x+c. Since the line passes through (-5, -3), substitute x with -5 and y with -3 to solve for c; -3 =3(-5)+c. Then c =12 and the equation of the line becomes; y =3x+12

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!