Factor completely.
49t^6 - 4k^8
a.) (7t³ + 2k^4)(7t³ - 2k^4)
b.) (7t³...
Mathematics, 01.10.2019 10:30, xxmimi7xx
Factor completely.
49t^6 - 4k^8
a.) (7t³ + 2k^4)(7t³ - 2k^4)
b.) (7t³ - 2k^4)(7t³ - 2k^4)
³ + 2k^4)(7t³ + 2k^4)
Answers: 1
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