If sec0+tan0=p, then find the value of cosec0.

Step-by-step explanation:

p=sec0+tan0

=1/cos0 + sin0/cos0

=(1+sin0)/cos0

square both sides

(1+sin)^2 /cos^2 = p^2

(1+sin)^2/(1 - sin^2 ) = p^2

(1+sin)^2/((1-sin)(1+sin)) = p^2

(1+sin)/(1-sin)=p^2

1+sin=p^2-p^sin

sin+p^2sin=p^2-1

sin(1+p^2)=(p^2-1)

sin=(1-p^2)/(1+p^2)

cosec=1/sin

=(1+p^2)/(1-p^2)

its line 2 i just added the rest or else it wouldn't let me answer