Abcd is a square
the measures shown in the diagram are to the nearest meter
find the least possible area of the shaded region
( plz idk what it means by least possible area)
plz me solve this : ))

you have to find the upper and lower bound of each measurement:

LB of 12 (nearest m) is 11.5m

UB of 12 is 12.5m

cuz anything between the bounds to the nearest metre will give 12

LB of 6 is 5.5

cuz any numbers between 5.5 and 6 rounded to the nearest whole number is 6

UB 6 is 6.5

cuz any numbers between 6 and 6.5 will round down to the nearest metre as 6

LB of 7 is 6.5

UB of 7 is 7.5

for the LEAST possible area you have to try and get the lowest possible value.

to get the lowest number, you have to do the LB - UB because a small number - a large number will give u a small number.

first find the area of the small rectangle and it has to be the largest area possible so you can minus a big number later on.

to do this multiply the upper bounds:

6.5 × 7.5 = 48.75 m squared

then find the area of the large square but this time you use the lower bounds.

11.5 × 11.5 = 132.25m squared

then minus these numbers.

132.25 - 48.75

= 83.5 m squared

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.