An astronaut drops a rock into a crater on the moon. the distance, d(t), in meters, the rock travels after t seconds can be modeled by d(t)=0.8t^2. what is the average speed, in meters per second, of the rock between 5 and 10 seconds after it was dropped?

Step-by-step explanation:

Given equation: , d(t), in meters, the rock travels after t seconds .

At t=5

The rock travels distance=

At t=10

The rock travels distance=

Total distance traveled by rock 5 and 10 seconds after it was dropped

=80-20=60 m

Total time =10-5=5 seconds

We know that the average speed =

step-by-step explanation:

1

i believe that the answer is

b. y-1=-2(x-4)

hope this !