Find the sine and cosine of the angle whose terminal side passes through (-7,2)

The sine = 0.2724 and the cosine =  -0.9615  to  4 decimal places.

Step-by-step explanation:

The point (-7,2) is in the second quadrant .

The sine is positive and the cosine is negative,.

The hypotenuse of the triangle in the second quadrant =  √((-7)^2 + 2^2)

= √53   ( by Pythagoras), the opposite side = 2 and the adjacent side = -7.

So the sine  of the angle is 2 /√53 and the cosine is  -7/√53.

or 0.2724 and -0.9615  to  4 decimal places.

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)