Arestaurant had n kg of sugar in its stock. then, 5 kg sugar was used to make the first dessert on
the menu. next, 3 kg sugar was used to make the second dessert on the menu. write an
expression to show how many kilograms of sugar were left in the stock, and then simplify the
expression.

Expression showing the sugar left is kg.

Step-by-step explanation:

We are given that,

Total number of sugar in the stock initially = n kg

Amount used for making 1st dessert = 5 kg

Amount of sugar left = kg

Again, Amount used for making 2nd dessert = 3 kg

Amount of sugar left = kg

i.e. Amount of sugar left = kg

Thus, the expression showing the sugar left is kg.

the answer is a

step-by-step explanation:

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}