Find the center of the circle that can be circumscribed about efg with e(4,4) f(4,2) g(8,2)

The center of the circle is (6 , 3)

Step-by-step explanation:

∵ The vertices of Δ EFG are E (4 , 4) , F (4 , 2) , G (8 , 2)

∵ The x-coordinates of E and E are equal ∴ EF is vertical

∵ The y-coordinates of F and G are equal ∴ FG is horizontal

∴ m∠EFG = 90°

∵ The circle is circumscribed about Δ EFG

∴ E , F , G lie on the circle

∵ m∠F = 90°

∴ EG is the diameter of the circle

∴ The center of the circle is the mid-point of EG

∵ The mid-point of EG is

∴ The center of the circle is (6 , 3)

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4

the answer would be a 24

step-by-step explanation:

c=2πr=2·π·3=24