Given that the quadrilateral is a kite, prove that.

Using SSS Congruence Property, we get ΔIKE ≅ ΔITE

Step-by-step explanation:

We are given a quadrilateral which is a 'kite'.

Now, according to the properties of Kite, we have that,

The two disjoint pairs of consecutive sides are congruent.

Thus, from the figure,

KI ≅ TI and KE ≅ TE

Also, side IE is the common side for both the triangles.

So, for ΔIKE ≅ ΔITE,

KI ≅ TI and KE ≅ TE and IE ≅ IE

Thus, using SSS Congruence Property, we get ΔIKE ≅ ΔITE

what are the statements

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.