What is the equation of a line that passes through the point (8, 1) and is perpendicular to the line whose equation is y=−2over3 x+5 ? enter your answer in the box.

y = 3/2x -11

Step-by-step explanation:

Perpendicular lines have negative reciprocal slopes.

This means for the line y = -2/3 x + 5 which is a slope of -2/3 its perpendicular slope will be 3/2.

Substitute m=3/2 and the point (8,1) into the point slope. Then simplify it.

y - 1 = 3/2(x-8)

y - 1 = 3/2x - 24/2

y - 1 = 3/2 x - 12

y = 3/2x -11

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq