The formula gives the height h of an object in free fall at time t and acceleration g.

h=1/2gt^2

solve for t.

sqrt(2h/g) = t

Step-by-step explanation:

h=1/2gt^2

We want to get t alone

First multiply by 2 to get rid of the fractions

2*h=2*1/2gt^2

2h = g t^2

Then divide by g on each side

2h/g = g t^2/g

2h/g = t^2

Then we need to take the square root of each side

sqrt(2h/g) = sqrt(t^2)

Normally we take the ± sqrt, but since time must be positive ( cannot have negative time)

sqrt(2h/g) = t

4

step-by-step explanation:

answer:  

step-by-step explanation:

here x represents the height of the pole,

and, the height of the shadow of the pole is 12 feet.

also, the angle of elevation from the top of the pole is 40°,

therefore,

by the low of sine,

which is the required equation for finding the value of x,