Last year 640 cars and 160 pickups were sold at a car lot. this year the number of cars sold increased by 10%. in the same period, the number of pickups sold decreased buy 10%. what is the percent of increase of sales at the car lot?

5.66% is the increase of sales at the car lot.

Step-by-step explanation:

Last year a car lot consist of 640 cars and 160 pickups.

This year there is a increase of 10% in cars

Therefore number of cars increased this year = 640×10% =

So total cars sold = 640+64 = 704

Percentage dip in sales of pickups this year is 10%, therefore number of pickups decreased this year = 160×10% =

So total pickups sold = 160-16 = 144

Total number of cars and pickups sold = 744+104 = 848

Now the percentage increase in number of cars = increase in lot×100/Lot size

=

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

a is the correct