Use the iteration
xn+1=5xnโ2x_{{n+1}} = \sqrt{5x_{n}-2}
x
n+1
...
Mathematics, 05.02.2020 06:57, iretae
Use the iteration
xn+1=5xnโ2x_{{n+1}} = \sqrt{5x_{n}-2}
x
n+1
=
5x
n
โ2
with
x0=5x_{{0}}=5
x
0
=5, to find a solution to the equation
Answers: 1
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