Mathematics
Mathematics, 05.02.2020 06:57, iretae

Use the iteration
xn+1=5xnโˆ’2x_{{n+1}} = \sqrt{5x_{n}-2}
x
n+1


=
5x
n


โˆ’2



with
x0=5x_{{0}}=5
x
0


=5, to find a solution to the equation

answer
Answers: 1

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Do you know the correct answer?
Use the iteration
xn+1=5xnโˆ’2x_{{n+1}} = \sqrt{5x_{n}-2}
x
n+1


...

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