The greatest common factor of 49a^4b^3 and 21a^4b^5

7a^4b^3

Explanation/Steps to solve:

First you separate 49 and 21 from the variables. Then you find their GCF.

The GCF of 49 is 21 is 7.

Then you find the GCF of the variables.

a^4b^3 and a^4b^5

how many As and Bs do they have in common?

both variables have 4 As and both have 3 Bs. It can't be 5 Bs since the other variable only has 3. 3 is less than 5 which means that there can be a 3 in the other variable (b^5).

So we rewrite how much As and Bs they have.

4 As = a^4

3 Bs = b^3

---> a^4b^3

then we combine both the GCF of the numbers and the variables,

7a^4b^3

$8

step-by-step explanation:

it is pretty much backwards.

you take the 4x2 multiply that, and that is = $8