Write a quadratic function whose zeros are -2 and -10

f(x) = x^2 + 12x + 20

Step-by-step explanation:

What is meant is that write a function that when - 2 is put in for x, the function goes to 0.

More formally f(-2) = 0.

So the function you want is f(x) = y = (x + 2)(x + 10) which is

f(x) = x^2 + 10x + 2x + 20

f(x) = x^2 + 12x + 20

Now  put - 2 into this function.

f(-2)= (-2)^2 + 12(-2) + 20

f(-2) = 4 - 24 + 20

f(-2) = 4 + 20 - 24

f(-2) = 0

I'll leave you to do the same thing with - 10

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

s

step-by-step explanation: