Can two positive integers have their h. c.f and l. c.m as 12 and 512 respectively? justify.

Here is your answer

NO

Reason:

H.C.F. divides the L.C.M. completely.

Here 512 is not completely divided by 12

So, two numbers can't have their H.C.F and L.C.M as 12 and 512 respectively.

HOPE IT IS USEFUL

No.

Step-by-step explanation:

The  answer is no because 12 has a factor of 3 but 512 hasn't:

12 = 2*2*3

512 = 2^9.

The LCM  would have to have 3 as one of its factors.

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

if the probability is 1/12, 75 people will receive a $25 gift card

step-by-step explanation: