Probability

a set of cards contains four suits. two suits are red, and two suits are black. in each suit there are cards numbered from 2 to 10 as well as a jack, a queen, a king, and an ace. consider the following probability for one card selected at random.

p(the selected card is a five or a black card)

the probability is:

7/13

Step-by-step explanation:

To do this, we find the probability of getting a black card, and getting a five but we have to subtract out the black fives.

There are 26 black cards out of the 52 cards in the set.

The are 4 fives out of the 52 cards in the set.

That would mean that 2 of the fives are black. If we didn't subtract the black fives, we would be overcounting.

Therefore we have 26/52 + 4/52 - 2/52 = 28/52 = 14/26 = 7/13

6.5

step-by-step explanation:

you said it was in the question

~courtney