The areas of two similar triangles are 72dm^2 and 50dm^2. the sum of their perimeters is 226dm. what is the perimeter of each of these triangles?

i will mark the first right answer as branliest no explanation needed just an answer.

Per2 = 102.727 dm

Per1 = 123.272 dm

Step-by-step explanation:

We know that the area of similar triangles are related to the square of their perimeters.

This means that

(Per1^2)/(Per2^2)  =  Area1 / Area2

If we take the square root of the previous equation

(Per1)/(Per2)  =  

(Per1)/(Per2)  =  

(Per1)/(Per2) = 1.2

We also know that

Per1 + Per2 = 226 dm

So,

1.2*Per2 + Per2 = 226 dm

2.2*Per2 = 226 dm

Per2 = 102.727 dm

Per1 = 1.2*Per2 = 123.272 dm

76%

step-by-step explanation:

24% are dogs and the remaining is 76% because 100-24=76

the correct answer is

c. 4

step-by-step explanation:

the given polynomial is

the degree of the polynomial is the highest exponent which is 4.

the -4 is called the leading coefficient.

this polynomial has only one term so it is a monomial.

the correct answer is option c.