The student council is sponsoring a concert as a fundraiser. tickets are $3 for student and $5 for adults. the student council wants to raise at least $1000. if 200 students attend, how many adults must attend? write and solve an inequality

Inequality is 3x + 5y ≥ 1000

At least 80 adults must attend the fundraiser.

Step-by-step explanation:

Let the number of students = x and the number of adults = y.

Also, each adult and student ticket is sold for $5 and $3.

Since, the student council wants to raise at least $1000.

The inequality representing the situation is,

3x + 5y ≥ 1000

We have total number of students attended the fundraiser are 200. So, x = 200.

That is,

3×200 + 5y ≥ 1000

i.e. 600 + 5y ≥ 1000

i.e. 5y ≥ 1000 - 600

i.e. 5y ≥ 400

i.e. y ≥ 80

Thus, we get that at least 80 adults must attend the fundraiser.

it could 14.28 but if its not that one then it has to be the 17 one. hope this ! : )

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i don't know

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