Joseph has $10,000 to invest. he can go to yankee bank that pays 5% simple interest or met bank that pays 4% interest compounded annually. at how many years will met bank be the better choice?

After 12 years ( approx )

Step-by-step explanation:

Let after t years the amount in met bank will exceed to the amount in Yankee bank,

For Yankee bank,

The principal amount, P = $ 10,000

Simple annual interest rate, r = 5 %

Hence, the amount in this bank after x years,

Now, For Met bank,

The principal amount, P = $ 10,000

Compound annual interest rate, r = 4 %

Hence, the amount in this bank after x years,

⇒For exceeding,

By the below graph, the above condition occurs after intersection of and at (11.919, 15959.341)

Hence, after x = 11.919 ≈ 12 years the amount in Met bank will be greater than that of Yankee bank.

⇒ For 12 years Met Bank will be the better choice.

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

$35.59 in pounds

step-by-step explanation: