In a carnival game you can either throw a target a which yields a $7 prize 12% of the time target b which yields a $3 prize 48% of the time. find the expected value of target b

The expected value of Target B is $ 1.44.

Step-by-step explanation:

Since,

Expected value = An outcome × its probability

Here, We have to find out the expected value of target B,

Given,

The probability of getting the price from target B = 48 % = 0.48,

Also, the value of getting the price from the target B = $ 3,

Hence, the expected value of Target B = 3 × 0.48 = $ 1.44

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step-by-step explanation:

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b