Will mark brainliest! find the equation of the line with slope −7 which goes through the point (−5,5).

  y -5 = -7(x +5)

Step-by-step explanation:

The point-slope form of the equation for a line is usually used for this purpose. For point (h, k), the line with slope m through it is given by ...

  y -k = m(x -h)

Filling in the given numbers, you get the equation ...

  y -5 = -7(x +5)

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This can be rearranged to any of several other forms:

  y = -7x -30 . . . . . slope-intercept form

  7x + y = -30 . . . . standard form

  x/(-30/7) + y/(-30) = 1 . . . . . intercept form

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.