Which polynomial function has a root of 1 with multiplicity 2 and a root of 6 with multiplicity 1? f(x) = (x – 1)(x – 6) f(x) = 2(x – 1)(x – 6) f(x) = (x – 1)(x – 1)(x – 6) f(x) = (x – 1)(x – 6)(x – 6)

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Step-by-step explanation:

The multiplicity of the root of a polynomial function refers to the number of times the root repeats itself.

If a polynomial function has a root of 1 with multiplicity 2, then is a factor of the polynomial.

If a polynomial function has a root of 6 with multiplicity 1, then is a factor of the polynomial.

The polynomial can be written as

or

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5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116