Triangle abc is translated according to the rule (x, y) → (x + 2, y – 8). if the coordinates of the pre-image of point b are (4, –5), what are the coordinates of b'?

(2, 3)
(1, –9)
(–3, –4)
(6, –13)

(6, –13)

Step-by-step explanation:

Points are translated according to the rule (x, y) → (x + 2, y – 8)

Therefore;

B → B'; will be;

(4, –5) → ( 4 + 2, -5 -8)

            → (6, -13 )

= (6, -13)

Therefore; the image of B or B' is (6,-13)

 The correct option is (D) (6, -13).

Step-by-step explanation:  Given that triangle ABC is translated according to the following rule

(x, y) → (x + 2, y – 8).

We are to find the co-ordinates of B' if the coordinates of the pre-image of point B are (4, –5).

Given that

the point (x, y) is translated to (x + 2, y - 8).

Therefore, the point B(4, -5) will be translated to

B'(4 + 2, -5 - 8) = B'(6, -13).

Thus, the co-ordinates of B' are (6, -13).

Option (D) is CORRECT.

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)