Atruck has a 20 gallon gas tank that is full. every three hours, the car uses 5 gallon of gas until it runs out.

what is the slope:

what is the y-intercep:

what is the equation

x l y

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how much gas will be left 10 hours?

how long will it take for the truck to have 6.8 gallons?

slope = 5/3

y - intercept is 0.

y = 5/3x is the required equation.

3.33 gallons of gas left.

4.08 hours

Step-by-step explanation:

Given: A truck has 20 gallon of gas.

Every three hours, the car uses 5 gallons of gas.

1 hour = 5/3

That is the slope = 5/3

x(jpours)               y (gallons)

3                          5

6                         10

9                          15

12                         20

Now let's form the equation.

Let's take two coordinates (3, 5) and (6, 10)

Here  x1  = 3, y1 = 5, x2 = 6 and y2 = 10

Slope(m) = (y2 - y1) /(x2 - x1)

m = (10 - 5) / (6 - 3) = 5/3.

Now let's find the y-intercept b

y = mx +  b

5 = 5/3 (3) + b

5 = 5 + b

b = 5 - 5

b = 0

Therefore, y - intercept is 0.

y = 5/3x is the required equation.

Now we have to find how much gas left 10 hours

Now plug in x = 10, in the equation.

y = 5/3 (10)

y = 50/3

y = 16.67

It uses 16.67 gallons for 10 hours.

Number of gallons left after 10 hours = 20 -16.67 = 3.33 gallons of gas left.

Now we have to find how long will it take for the truck to have 6.8 gallons.

Plug in y = 6.8 in the equation, we get

6.8 = 5/3 x

x = 6.8 *3/5

x = 20.4/5

x = 4.08 hours

Thank you.

your question is incomplete, write all the numbers in the sequence that it tells you.  

step-by-step explanation:

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step-by-step explanation: