For the simple harmonic motion equation (see pic) what is the period?

Period of the given harmonic function is 1.

Step-by-step explanation:

In any harmonic function which is in the form of y = asin(bx+c) + d , we know

Period of this function will be represented as P =

Therefore for the given function d = 5 sin (2πt) we know the value of B is 2π.

So the period will be P =

The answer is period = 1

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584

the first one

step-by-step explanation:

just id the test.