What is the equation of a line that passes through the point (6,3) and is perpendicular to a line with a slope of -3/2

a. y= -2/3x-1

b. y=-2/3x+3

c. y=2/3x+1

d. y=2/3x+3

  none of the above

Step-by-step explanation:

The perpendicular line will have a slope that is the negative reciprocal of the given slope, so it is ...

  m = -1/(-3/2) = 2/3

The point-slope form of the equation of the line with slope m through point (h, k) can be written ...

  y = m(x -h) +k

For this slope and the point (6, 3), the equation of the line is ...

  y = (2/3)(x -6) +3

  y = 2/3x -4 +3

  y = 2/3x -1 . . . . . matches none of the offered choices

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The attached graph shows this equation is the one that goes through the given point.

the answer i think is a)

step-by-step explanation:

step-by-step explanation: