∠bec is formed inside a circle by two intersecting chords. if minor arc bd = 94 and minor arc ac = 166, what is the measure of ∠ bec? a) 44° b) 47° c) 50° d) 53°

∠BEC = 50°

Step-by-step explanation:

For better understanding of the solution, see the attached figure of the problem :

Minor arc BD = 94

Minor arc AC = 166

Now, the angle formed by the intersection of the two chords is ∠BED

And, the angle formed by the intersection of two chords is half the sum of angle measures of the corresponding chords.

Now, ∠BED + ∠BEC = 180 ( Adjacent angles )

⇒ ∠BEC = 180 - 130

⇒ ∠BEC = 50°

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

a² + b²= c²

24² + 7² = c²

c= 25