Archie and veronic are located one mile (5280 ft) apart on the ground. they observe a blimp directly over the road between them. archie measures the angle of elevation from the ground to the blimp to be 53 degrees. veronica measures the angle of elevation from the ground to the blimp to be 22 degrees. how far above the ground is the blimp?

The height of the blimp above the ground = 1635.363039 feet.

Step-by-step explanation:

Archie and Veronica are located one mile (5280 ft) apart on the ground. So AV = 5280 feet.

Suppose the height of blimp above the ground is XB = h feet.

Archie measures the angle of elevation from the ground to the blimp to be 53 degrees. So angle ∠BAX = 53°.

Veronica measures the angle of elevation from the ground to the blimp to be 22 degrees. So angle ∠BVX = 22°.

Considering Right triangle ΔAXB, cot(A) = AX / XB

AX = XB*cot(A) = h*cot(53°) = 0.75355405*h

Considering Right triangle ΔVXB, cot(B) = VX / XB

VX = XB*cot(B) = h*cot(22°) = 2.475086853*h

We know AV = 5280 and AX + VX = AV.

So AX + VX = 5280.

0.75355405*h + 2.475086853*h = 5280.

3.228640904*h = 5280.

h = 5280 / 3.228640904 = 1635.363039 feet.

Hence, the height of the blimp above the ground = 1635.363039 feet.

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;