You roll a number cube twice. what is the probability of rolling a 2 first and then rolling an odd number? 1/36,1/12,1/9,1/4

A = event of rolling a 2 on the first roll

P(A) = 1/6 because there is only one "2" out of six labels total on the number cube.

B = event of rolling an odd number on the second roll

P(B) = 3/6 = 1/2 since there are three odd numbers {1,3,5} out of six total

The events A and B are independent, so we can multiply the probabilities

P(A and B) = probability of both events happening simultaenously

P(A and B) = P(A)*P(B)

P(A and B) = (1/6)*(1/2)

P(A and B) = (1*1)/(6*2)

P(A and B) = 1/12

Note: The fraction 1/12 is approximately equal to 0.0833

the inequality is:

250c+180g≥950

step-by-step explanation:

let c denotes the number of days in a week   miyoko worked as a cryptographer.

and g denotes the number of days in a week she works as a geologist.

now we are given that she earns $250 for every day she works as a cryptographer,and earns $180 for every day she works as a geologist.

now miyoko's goal is to earn more than $950 this week.

hence, the inequality could be represented as:

250c+180g≥950

describing distributions is one of the key skills you’ll need to earn a high score on the ap statistics exam. if you need proof of this, just flip through some past exam questions, which can be found at the collegeboard website. you’ll notice that the first free response question is almost always a question requiring you to look at a graph and describe it.

step-by-step explanation: just trying to get points sorry : (