![\footnotesize{\text{subtract 1 from both sides}}\\\\9\sin^4x=1\\\\\footnotesize{\text{divide both sides by 9}}\\\\\sin^4x=\dfrac{1}{9}\to\sin x=\pm\sqrt[4]{\dfrac{1}{9}}\\\\\sin x=\pm\dfrac{1}{\sqrt3}\cdot\dfrac{\sqrt3}{\sqrt3}\\\\\sin x=\pm\dfrac{\sqrt3}{3}\\\\\text{look at the picture}](/tpl/images/0500/2514/fc771.png)
Ijust need with the second part. !
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