Aline has a slope of -13. there is a second line that passes through points (-7,-5) and (6,-4) . would these lines be parallel , perpendicular or neither ?

Work Shown:

Use the slope formula to find the slope of the line through the two given points.

m = (y2 - y1)/(x2 - x1)

m = (-4 - (-5))/(6 - (-7))

m = (-4 + 5)/(6 + 7)

m = 1/13

The slope of the line through the two given points is 1/13.

This is not equal to -13, which was the slope of the first line, so the two lines are not parallel.

However, the two lines are perpendicular because multiplying the two slope values leads to -1

(slope1)*(slope2) = (-13)*(1/13) = -1

note: It might help to think of -13 as -13/1 to help multiply the fractions.

it should be a and d. lmk if i'm wrong xd

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.