Hi there!

can i get some with number 16 and 20 ? ! show your work : )

!

16. We could write

(basically find the quotient/remainder upon dividing by ). Then as , diverges to from the left, and to from the right. So the limit does not exist.

20. Factorize the numerator:

We're considering the limit as , which also means that it's not the case that . Because of this, we can cancel the factor of in both numerator and denominator:

exists for all values of (i.e. it's continuous on its domain), so the limit is the value of at , so

c. 4 1/4 pounds

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: