What is the measure of {ced and {acd?

Part a)

Part b)

Step-by-step explanation:

step 1

Find the measure of angle ACB

we know that

The sum of the measures of interior angle of a triangle must be equal to

so

In the triangle ABC

step 2

Find the measure of angle ACD

we know that

-------> by supplementary angles

we have

substitute

step 3

Find the measure of angle CED

we know that

m<DCE=m<ACB ------> by vertical angles

so

Remember that

The sum of the measures of interior angle of a triangle must be equal to

so

In the triangle CDE

the 2 figures are congruent bc if you reflect abcd over the y axis then over the d axis the figures overlap

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.