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the equation of a circle is x^2+y^2+10x-4y-12=0. put the equation in standard form. what are the center and radius of the circle? show your work.

Step-by-step explanation:

note :

hello :

an equation of the circle Center at the A(a,b) and ridus : r is :

(x-a)² +(y-b)² = r² ( standard form )

x²+y²+10x-4y-12=0

(x² +10x) + (y²- 4y) -12 = 0

(x² +2(5)(x) +5² -5²) + ( y² -2(2)(y) +2² -2²) -12 = 0

(x + 5)² - 25 + ( y - 2 )² - 4 -12 = 0

(x + 5 )² + ( y - 2 )² = 41 ( standard form )

the center is the point A(-5 ; 2) and   ridus  r = √41

don't know sorry bru

step-by-step explanation: